2x^2-70x=-600

Solution for 2x^2-70x=-600 equation:

2x^2-70x=-600

We move all terms to the left:

2x^2-70x-(-600)=0

We add all the numbers together, and all the variables

2x^2-70x+600=0

a = 2; b = -70; c = +600;
Δ = b2-4ac
Δ = -702-4·2·600
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-10}{2*2}=\frac{60}{4}
=15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+10}{2*2}=\frac{80}{4}
=20
$